vb.net need a command to return the index # of a value in array

[Babyboy]

hello everyone, its been a while, usually im good at figuring things myself, but i cant figure how to even google this.

if arrayname.contains(number) = true
return the position in the array of the found number




arrayname(1,2,3,4,5,6,7) as integer
if arrayname.contains(7) = true
intIndexNumber= ****the code i need to return the position of the number 7)**********

any ideas?

[Xeda112358]

I am absolutely not familiar with that language whatsoever. I do know that if I were to do this in TI-BASIC, I would do 1+sum(not(cumSum(7=L1

I don't know if the language you are working with would return a list of boolean comparisons, but if it does, you can take advantage of that. (meaning in TI-BASIC, 7=L1 using your array above would return {0,0,0,0,0,0,1})

[Babyboy]

Ok, I spent years with Ti-Basic, but i have no idea what the F*** that code does, could you take me through it?

[Xeda112358]

1+sum(not(cumSum(7=L1

So to break it down, say we have L1 be {1,3,7,4,3,3,1,2}

7=L1 returns {0,0,1,0,0,0,0,0}
cumSum( of that returns {0,0,1,1,1,1,1,1}
not( of that returns {1,1,0,0,0,0,0,0}
sum( of that returns 2
add 1 to get the location of the first 7

So what if there are two sevens?
{1,3,7,4,3,7,1,2}

[Babyboy]

F******* beautiful

[Xeda112358]

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