Code:
:26→K
:1.1→B
:{4Ans→A
:ClrHome
:For(A,1,E2
:randInt(1,16)+.1randInt(1,8→C
:Repeat C=Ans(1
:A→dim(⌊A
:⌊A(1
:Output(10fPart(Ans),int(Ans),"O
:Output(10fPart(B),int(B),"   // 1 space
:Output(10fPart(C),int(C),"*
:getKey
:If Ans=45
:Goto 0
:If Ans=34 or 2>abs(Ans-25
:Ans→K
:⌊A(A→B
:⌊A(1)+(K=26)-(K=24)+.1((K=34)-(K=25
:If max(LA=Ans
:Goto 0
:Ans+16(not(int(Ans))-(17=int(Ans)))+.8(not(fPart(Ans))-(.9=fPart(Ans
:augment({Ans},⌊A→A
:End
:augment(Ans,{Ans(A→A
:End
:Lbl 0
:ClrHome
:A


That E on the 5th line is Euler's number, right? What is it's role on the code?

I think I can interpret the rest of the code by myself, but I have no idea what Euler's number does.
That's not Euler's number (which is generally a lowercase e). That's the scientific-notation E; it's short for *10^. So E2 is just shorthand for 100. Doing it as E2 saves a byte. This is more useful for larger numbers, like E5 for 100000.
Oh, alright thanks
  
Register to Join the Conversation
Have your own thoughts to add to this or any other topic? Want to ask a question, offer a suggestion, share your own programs and projects, upload a file to the file archives, get help with calculator and computer programming, or simply chat with like-minded coders and tech and calculator enthusiasts via the site-wide AJAX SAX widget? Registration for a free Cemetech account only takes a minute.

» Go to Registration page
Page 1 of 1
» All times are UTC - 5 Hours
 
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum

 

Advertisement