There's no such thing as an 8-bit address.
I didn't think so either (excluding relative addresses), but that still leaves the ti83plus.inc thing unexplained.
Those are equates; in this case, that is a context which you would pass to _JError (I think).
Technically, an 8 bit address is possible, but they don't exist in the z80 aside from relative addressing, but a pure 8 bit processor would be forced to use an 8 bit address space.
Technically, an 8 bit address is possible, but they don't exist in the z80 aside from relative addressing, but a pure 8 bit processor would be forced to use an 8 bit address space.
- 23 Apr 2007 05:35:05 pm
- Last edited by haveacalc on 23 Apr 2007 05:42:33 pm; edited 2 times in total
Argh! There must be something wrong with this code, but I can't figure out what. It's supposed to shade some of the graph screen. Here's the original code:
Code:
Let's see if I can translate it correctly:
Code:
I might have b and c mixed around, but I wouldn't think that would cause the program to crash.
Code:
21409301EEEE3EFF
77230C20010420F8C9Let's see if I can translate it correctly:
Code:
ld hl,9340h
ld bc,EEEEh
ld a,FFh
label:
ld (hl),a
inc hl
inc c
jr NZ,next
inc b
next:
jr NZ,label
retI might have b and c mixed around, but I wouldn't think that would cause the program to crash.
- 23 Apr 2007 05:37:20 pm
- Last edited by KermMartian on 23 Apr 2007 05:45:25 pm; edited 1 time in total
For starters, the graph buffer is DEFINITELY not at $4093 - that's in ROM. It's somewhere above $8000; double-check your tables.
Edit: no fair, you edited it.
Edit: no fair, you edited it.
Since I couldn't think of a better way to do this (16-bit incrementing doesn't alter flags), it's supposed to increment bc (in a manual, makeshift way) until it gets to $0000, when the program will stop. $EEEE is just a random number that I put into bc, hoping that it will cause a small enough amount of loopage that my program will only shade part of the graph screen and not any other memory.
How are you people translating this? Do you just know what the asm = in hex? o.O
Any fool can use a computer. Many do.
No, they aren't magic. Well most of them aren't.
We use what's called a z80 instruction set reference. The good ones include the instruction mnemonic and assembled hexadecimal/binary value as well as timings, size and flags.
For example, WikiTI.
We use what's called a z80 instruction set reference. The good ones include the instruction mnemonic and assembled hexadecimal/binary value as well as timings, size and flags.
For example, WikiTI.
Check if bc is zero:
Code:
Edit: Also, $EEEE is not a good idea, because it will go through the loop $1112 times, and the graph buffer has only $0300 bytes in it.
Code:
ld a,b
or cEdit: Also, $EEEE is not a good idea, because it will go through the loop $1112 times, and the graph buffer has only $0300 bytes in it.
calc84maniac wrote:
Kerm edited his post, the cheater...
I also edited haveacalc's post to match mine, but then he edited his back. 
$EEEE is definitely a bad idea. Just load $300 into bc and run the loop, decrementing bc each time and doing calc's zero-check at each loop.
I completely forgot about "or", which is sad since that's one of the groups of instructions that I memorized the opcodes for. 
It works now, though:
Code:
or:
Code:
Thanks again to those those who helped. I think I'll refrain from asking questions from now on; not only do think that I could figure it out eventually, but it's pretty bad for my problem-solving skills to rely on others so often.
It works now, though:Code:
214093010003
36FF230B78B120F8C9Code:
ld hl,9340h
ld bc,300h
theplacetobe:
ld (hl),FFh
inc hl
dec bc
ld a,b
or c
jr NZ,theplacetobe
retThanks again to those those who helped. I think I'll refrain from asking questions from now on; not only do think that I could figure it out eventually, but it's pretty bad for my problem-solving skills to rely on others so often.
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